a mixture of O2 ans gas "Y" (mol.wt.=80) in the mole ratio a:b has a mean molecular weight 40 . what would be mean molecular weight if the gases are mixed in the ratio b:a under identical condition ?
Answers
as we know mixture of oxygen and gas y have
molecular weight of O2 is 32
molecular weight of gas Y is 80
and the mean molecular weight is 40
under identical condition when there is a: b
(32xa) + (80 x b)/ a+b = 40
32a + 80 b = 40a + 40b
80b-40b= 40a-32a
40b= 8a, a=40b/8,
a=5b...........(1)
when there is b:a
(32b+ 80a)/a+b
putting the value of a
32b + 80 (5b)/ a+b
32b + 400b/ 6b
432b/ 6b = 72
Answer:
Explanation:
as we know mixture of oxygen and gas y have
molecular weight of O2 is 32
molecular weight of gas Y is 80
and the mean molecular weight is 40
under identical condition when there is a: b
(32xa) + (80 x b)/ a+b = 40
32a + 80 b = 40a + 40b
80b-40b= 40a-32a
40b= 8a, a=40b/8,
a=5b...........(1)
when there is b:a
(32b+ 80a)/a+b
putting the value of a
32b + 80 (5b)/ a+b
32b + 400b/ 6b
432b/ 6b = 72