Chemistry, asked by StrongGirl, 9 months ago

A mixture of one mole each of
 o_{2}(g) \: h_{2}(g)  \: he(g)
exits in a container of volume V at temperature T. in which partial pressure of H_2(g) is 2 at. the total pressure in the container is ?​

Answers

Answered by abhi178
0

A mixture of one mole each of O2 , H2 and He exits in a container of volume V at temperature T. in which partial pressure of H2 is 2 atm.

To find : The total pressure in the container is..

solution : according to Dalton's law of partial pressure,

when two or more non - reactive gas is mixed in a container, then total pressure in the container must be sum of partial pressure of each of gas.

i.e., P = P₁ + P₂ + P₃ ...

here three gases present in the same amount in a container at same pressure.

so, partial pressure of H2 = particle pressure of O2 = partial pressure of He = 2atm

now total pressure = P₁ + P₂ + P₃

= 2 atm + 2 atm + 2 atm

= 6 atm

Therefore the total pressure in the container is 6 atm.

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