A mixture of ozone and oxygen containing 20% by volume of ozone , diffused through a porous plug in 172 seconds while the same volume of pure oxygen took 164 seconds to diffuse through the same plug. Calculate the relative density of ozone .
Answers
The relative density of ozone will be 1.5
Explanation :
According to graham's law of diffusion, the rate of diffusion is inversely proportional to square root of density.
=> R₁/R₂ = √(d₂/d₁)
where ,
R₁/R₂ = rate of diffusion of oxygen/rate of diffusion of mixture = 172/164
d₁ = density of oxygen
d₂ = density of mixture = 0.8d₁ + 0.2d
Hence ,
172/164 = √(0.8d₁ + 0.2d)/d₁
=> 1.048² = 0.8 + 0.2(d/d₁)
=> 1.1 = 0.8 + 0.2(d/d₁)
=> 0.2(d/d₁) = 0.3
=> d/d₁ = 1.5
Hence the relative density of ozone will be 1.5
Answer:
The relative density of ozone will be 1.5
Explanation :
According to graham's law of diffusion, the rate of diffusion is inversely proportional to square root of density.
=> R₁/R₂ = √(d₂/d₁)
where ,
R₁/R₂ = rate of diffusion of oxygen/rate of diffusion of mixture = 172/164
d₁ = density of oxygen
d₂ = density of mixture = 0.8d₁ + 0.2d
Hence ,
172/164 = √(0.8d₁ + 0.2d)/d₁
=> 1.048² = 0.8 + 0.2(d/d₁)
=> 1.1 = 0.8 + 0.2(d/d₁)
=> 0.2(d/d₁) = 0.3
=> d/d₁ = 1.5
Hence the relative density of ozone will be 1.5