A mixture of sand and water contains 20% sand by weight of it 20kg water is evaporated and the mixture now contains 30% sand
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Answer:
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Step-by-step explanation:
Let the amount of water in the original solution =x kg.
Then the amount of salt present in 15% of this solution =
100
15x
kg=
20
3x
kg.
After 30 kg water evaporates, the amount of water =(x=30) kg.
So, the new concentration =
x−30
20
3x
×100.
Then, by the given condition,
x−30
20
3x
×100=20
⇒4x−120=3x
⇒x=120 kg
So, the quantity of the original solution =120 kg.
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