Question

A mixture of So2 and O2 at 1atm pressure in the molar ratio 2:1 in passed through a catalyst 1170©. the existing gas is suddenly chill and analyze and it is found to contain 87% So3 by volume. then calculate the Kp for the reaction​

Answer 1

Explanation:

The volume of SO

2

and O

2

at equilibrium=(100−87)=13mL

Volume if SO

2

=

3

2

×13=8.67mL

volume of oxygen =

3

1

×13=4.33mL

p

SO

3

=

100

87

×1=0.87atm

p

SO

2

=

100

8.67

×1=0.0867atm

p

O

2

=

100

4.33

×1=0.0433atm

K

p

=

p

SO

3

×(p

O

2

)

1/2

p

SO

3

=

0.0867×0.0433

2

0.87

=48.24