Question

a mixture of sodium (NACL ) and anhydrous sodium carbonate (Na2CO3 ) has a mole ratio 2: 1 .it is dissolved in water and treated wirh BaCl2 solution. the mass of Ba2CO3 precipated is 98.5 gm . calculate the mass ( in gm) of nacl in the mixture ?

Answer 1

answer :-


chemical eq :-

Na2CO3 + BaCl2 ---------> 2NaCl + BaCO3
0.5 mol 0.5 mol

so ,

mol of NaCl = 1mol

mass of NaCl in mixture = 58.5g


Be brainly

Answer 2

Answer:

chemical eq :-

Na2CO3 + BaCl2 ---------> 2NaCl + BaCO3

0.5 mol 0.5 mol

so ,

mol of NaCl = 1mol

mass of NaCl in mixture = 58.5g