A mixture of two miscible liquid ( ethanol and water) has the number of phase equal to
Answers
Answer:
ANSWER
In solution x
A
=0.30; x
B
=0.70
In vapour phase, y
A
=0.60; y
B
=0.40
Using Dalton's law and Raoult's law
y
A
=0.60=
P
T
P
A
=
P
A
+P
B
P
A
=
0.30p
A
o
+0.70p
B
o
0.30p
A
o
y
B
=
0.30p
A
o
+0.70p
B
o
0.70p
B
o
y
B
y
A
=
0.40
0.60
=
0.70p
B
o
0.30p
A
o
p
B
o
p
A
o
=
0.40×0.30
0.60×0.70
=3.5
Option B is correct.
Answer:
The correct answer will be phase one for the mixture of two miscible liquids.
Explanation:
What is miscible liquids?
Miscible liquids are those that mix with other liquids. Immiscible liquids are those that do not mix with other liquids. Water and milk, for instance, mix well. Water and coconut oil, for instance, cannot mix.
That is according to the Gibb's phase rule. It claims that the quantity of components and phases might affect the degree of freedom. Water and ethanol mix perfectly to create a solution. Such mixes only have one phase. The degrees of freedom for a compound in a closed physical system are examined using the Gibbs Phase Rule. According to the rule, the number of components minus the precise number of phases always equals the freedom degree. The degrees of freedom for a compound in a closed physical system are examined using the Gibbs Phase Rule. According to the rule, the number of components minus the precise number of phases always equals the freedom degree.
To know more about miscible liquids, check out:
https://brainly.in/question/40605941
To know more about gibb's phase rule, check out:
https://brainly.in/question/40608815
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