A mixture of water and milk contain 80%milk. in 50% of such mixture .how many litre of water required to increase the %of water 250%
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On addition of extra water, quantity of water becomes [10+x] lit. Therefore the fraction of water in the mixture becomes [10+x]/[50+x]. The new % of water becomes [10+x]/[50+x]. 100%
i.e. [10+x]/[50+x]. 100%=50%
or, [10+x]/[50+x]. 100 = 50
or, [10+x]/[50+x].2 =1
or, 20+2x=50+x
or, 2x-x=50–20
or x=30
therefore quantity of water to be asses is 30 lit.
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