Question

A MNT ~ AQRS. Length of altitude drawn from point T is 5 and length of altitude
A(AMNT)
drawn from point Sis 9. Find the ratio
A( A QRS)​

Answer 1

Answer:

A(ΔMNT)/A(ΔQRS) = 25/81

Step-by-step explanation:

ΔMNT~ΔQRS. Length of altitude drawn from point T is 5 and length of altitude drawn from point S is 9

ΔMNT ≅ ΔQRS

MN/QR = NT/RS / TM/SQ

Altitude drawn would also be in similar ration

so MN/QR = 5/9   - eq 1

Area of ΔMNT = (1/2) MN * 5

Area of ΔQRS = (1/2) QR * 9

Area of ΔMNT/Area of ΔQRS  = ( (1/2) MN * 5 ) / (  (1/2) QR * 9)

= (MN/QR)(5/9)

putting value of MN/QR from eq 1

= (5/9)(5/9)

= 25/81

A(ΔMNT)/A(ΔQRS) = 25/81