A mobile company manufactured 2000 mobile in the fifth month and 2750 mobiles in the 8th month. Assuming that the production increases informally by fixed number every month find the production of mobiles in the first month and in the 10th month.
Answers
Answer:
Step-by-step explanation:
Units in 5th month=2000
Units in 8th month=2750
Therefore in 3 months increase is 750
Therefore increase in one month is 750/3=250
Now in fifth month units are 2000
Therefore in first month they will be 2000-4(250) ...(4 because there are four months between 1st and 5th month)
2000-1000=1000units
In 8 months there are 2750units
Therefore in 10 Montana there will be
2750+2(250)=2750+500=3250 units
Answer:
Production of mobiles in first month = 1000 units and in 10th month = 3250 units.
Step-by-step explanation:
Mobiles manufactured in 5th month are 2000 and in 8th month are 2750.
Since production increases by fixed number in every month then it can be considered as an Arithmetic Progression (AP).
Let a be the first term and d be the common difference.
Now, according to the formula for the nth term,
aₙ = a + (n - 1)d
a₅ = a + 4d = 2000 .......(i)
a₈ = a + 7d = 2750 ........(ii)
Solving the equations (i) and (ii) for a and d we get,
a = 1000 and d = 250
Now, a₁ = a = 1000
a₁₀ = a + 9d = 1000 + 9 × 250
a₁₀ = 3250
Thus, first month a₁ = 1000 and,
10th month a₁₀ = 3250.