A mobile phone and its case cost ₹ 1100 in total. The price of the mobile"
"phone is ₹ 1000 more than its case. What is the price of the mobile phone?"
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Answer:
cp={$105}
PREMISES
ASSUMPTIONS
Let pc=phone case
Let cp=cell phone
Let the cost of the phone case=pc
Let the cost of the cell phone=pc+$100
CALCULATIONS
cp+pc=$110
(pc+$100)+pc=$110
2pc+$100=$110 (Addition is commutative)
2pc+($100-$100)=$110-$100
2pc+0=$10
2pc=$10
2pc/2=$10/2
pc=$10/2
pc=
$5
and,
if cp=pc+$100, then
cp=$5+$100
cp=
$105
PROOF
If cp=$105, then the equations
cp+pc=$110
$105+$5=$110 and
$110=$110 establish the root (zero) cp=$105 of the sum of cp+pc
Step-by-step explanation:
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