Question

A model engine accelerates forward from rest along a straight track at 10.0 m/s 2 for 3.0
seconds. It then accelerates forward at 16 m/s 2 for 5.0 seconds, and finally decelerates at 12
m/s 2 until it stops.
(a) Calculate how many seconds the engine was moving.

(b) What was its maximum velocity?

(c) Plot a velocity/time graph of its motion

(d) Find the total distance travelled

Answer 1

Answer:

for 1st v=30m/s using v= u +at

S= 45m using S= ut+ 1/2 at^2

for 2nd v= 110,S= 350m

for dece using above equ with v=0

0= 110 - 12t

t= 55/6

using V^2-u^2 =2aS

S= 504.166m

t = 3+ 5 +(55/6)= 103/6 = 17.1667s

max v = 110 m/s

total Distance= 899.1667m