Math, asked by licia4470, 6 months ago

A model rocket is launched from the roof of a building. Its flight path is modeled by the equation below, where h is the height of the rocket above the ground, in feet, and x is the time in seconds.

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Answered by dharman565
0

Answer:

A rocket is launched and its height above sea level t seconds after launch is given by the equation

An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters

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