Question

A model weighing 45 kg is standing on a pencil heel each having an area of cross-section of 2 cm square. Calculate the pressure exerted on the floor.(Acceleration due to gravity-10m/s²)​
First and correct answer will be mark as brainliest.

Answer 1

Answer:

5.625 * $10^{6}$ Pa

Explanation:

  Given: Mass = 45kg                             g = 10m/$s^{2}$

               Each heel area = 2$cm^{2}$       Total area of support = No. of heels * 2

                                                     =>  4 * 2     =     8$cm^{2}$

W = m * g        => 45 * 10                            => 450N

                            in C.G.S unit = 1N = $10^{5}$ dyne

                                  So, 450N = 450 * $10^{5}$ dyne

  P = Ft / A                       =>    $\frac{450 * 10^{5} }{8}$                      =>56.25 * $10^{5}$

                     => 5.625 * $10^{6}$ Pa