Question

A modem has a baud rate of 40 signals / seconds. If it is transmitted at the rate of 4800 bps, what is the coding rate?

Answer 1

Answer:

Your question is confusing, but if it you're sending a start bit, 8 bits of data, a parity bit, and two stop bits all encoded as one symbol, 2048 times a second, then that's 2 kilobaud where "kilo" = 2048. Then, since there's 12 bits per baud, the bit rate would be 12 bits * 2048 baud = 24576 bits per second.

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Answer 2

Answer:

is something missing in the question

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