a molecule at rest split into two nuclear part having radii in the ratio 1:2 their velocities are in the ratio?
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A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?
(a) 21/3: 1
(b) 1: 21/3
(c) 31/2:1
(d) 1:31/2
(a) 21/3: 1
(b) 1: 21/3
(c) 31/2:1
(d) 1:31/2
ruhipandey:
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✔️Given
Radius= 1:2
✔️Solution
According to the law of conservation of Linear momentum;
m1v1=m2v2
v1/v2=m2/m1=(R2/R1)³
v1/v2 =(2/1)³ = 8:1
✔️Thank you ‼
Radius= 1:2
✔️Solution
According to the law of conservation of Linear momentum;
m1v1=m2v2
v1/v2=m2/m1=(R2/R1)³
v1/v2 =(2/1)³ = 8:1
✔️Thank you ‼
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