A molecule has two isomers A and B. When pure A is prepared at the initial time, there is an exponential decay of the isomer A and concomitant rise of the B-form. The time constant for the decay is 100 minutes. After a long time we find 50% of A-form and 50% of B-form. After the equilibrium is reached, we follow one molecule of the B-form for one whole day. Which of the following will we likely observe?
A) The molecule remains in B-form
B) The molecule has become A
C) There is equal probability to find the molecule either in the A-form or in the B-form
D) There is inadequate data given in the problem to make any prediction
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Answer:
c
Explanation:
as equilibrium is reached so reaction is processed in both directions that is forward reaction =reverse reaction
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