Question

A molecule which possess both sp3 and sp3d2 hyd is.

Answer 1

Answer:

molecule have sp3 hybridisation  have triangonal panal

             

molecule have sp3d2 hybridisation have octahydral shape

Explanation:

Answer 2

Answer:

The molecule which possess both sp3 and sp3d2 hybridization is PCl5.

When it's in form of PCl4+ it's in sp3 hybridization.

When it's in form of PCl6- it's in sp3d2 hybridization.

Explanation :

In PCI5,

• the number of e pairs surrounding the centre atom P = 5 is zero.
• Hybridization - sp3d and
• number of lone pairs = 0.
• Trigonal bipyramidal in shape.

In PCI4+,

• the number of e pairs is 4,
• the number of lone pairs is 0,
• the hybridization is sp3, and
• the form is tetrahedral.

The number of e pairs in PCI6- is 6, the number of lone pairs is 0, the hybridisation is sp3d2, and the shape is octahedral.

In PCl4+, P hybridization is sp3.

We know that the configuration of P's outermost shell is P = 3s2 3p3.

The configuration in G.S will be 3s2 3p3.

Phosphorus has a "+" charge, indicating that it has lost one electron.

In ground state, the arrangement now appears like 3s2 3p2.

The arrangement in the excited state is 3s1 3p3.

The sp3 orbital will now be occupied by four Cl atoms.

As a result, configuration of PCl4+ is Sp3.

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