Question

A molecule with formula C4H80
gives 3 sets of peaks, a triplet at 1.2
ppm, a quartet at 2.5 ppm and a
singlet at 4 ppm. The relative
integral areas of these peaks
respectively are 3:2:3. What is the
possible molecular structure of this
compound?​

Answer 1

Answer:

possible molecular structure n propanol

Answer 2

Answer:

The possible molecular structure of a molecule with formula $C_{4}H_{8}O$ is$CH_{3}-CH_{2}-CO-C H_{3}$

Explanation:

Given molecular formula is $C_{4}H_{8}O$

The formula for degree of unsaturation (DOU)  is given by $x+1-\frac{y}{2} +\frac{z}{2}$

Where,

x is number of carbon atoms,

y is monovalent atoms like hydrogen, and halogen atoms,

z is trivalent atoms like Nitrogen.

Thus, by applying this formula to the given molecular formula,

$4+1-\frac{8}{2} +0=5-4=1$

The degree of unsaturation $1$ represents the presence of one double bond.

From the given data,

A triplet at $1.2$ ppm with the relative integral area $3$ represents the presence of $CH_{3}$ group contains the neighboring carbon with $2$ carbons.

A quartet at $2.5$ ppm with the relative integral area $2$ represents the presence of $CH_{2}$ group, contains the neighboring carbon with $3$ carbons.

A singlet at $4$ ppm with the relative integral area $3$ represents a $CH_{3}$ group contains the neighboring carbon $(C=O)$  without hydrogen atoms.

Thus, the possible molecular structure will be $CH_{3}-CH_{2}-CO-C H_{3}$.