Question

A monatomic gas at pressure p 1 and volume v 1 is compressed adiabatically to 1 th 8 its original volume. what is the final presssure of the gas

Answer 1

Given:
⇒ Initial pressure = P1
⇒ Initial Volume = V1
⇒ Final Volume = 1/8th of the initial volume
                           = V1/8

To find:            
⇒ Final Pressure, P2 = ?

Solution:
⇒ Since it is a monoatomic gas, γ = 5/3
⇒ (P1V1)^5/3 = P2 (V1/8)^5/3
⇒ P2 = P1 × 2^5
⇒ ∴P2 = 32P1

⇒ Thus, final pressure of the gas, P2 = 32P1.

:)

Answer 2

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