Question

A monatomic gas contained in vessel is subjected
to a thermodynamic process such that its pressure
changes with volume as shown in graph above, then
change in internal energy during process will be
1. Zero
2. 3PoVo
3. 3/2 PoVo
4. 5PoVo
​

Answer 1

Answer:

option 1 :zero will be the answer .

Answer 2

change in internal energy during the process will be zero.

From the graph, we can see the initial and final values of pressure and volume.

Initially

P = 2Po and V = Vo

Therefore P1V1 = 2PoVo

Finally

P = Po and V = 2Vo

Therefore P2V2 = 2PoVo

We can see that we have P1V1 = P2V2

therefore PV = Constant

Now we know that

PV = nRT

Therefore nRT = constant

Hence T = constant and ΔT = 0

Now the internal energy is ΔU = ncΔT

So, when ΔT = 0 then ΔU will also be 0.

change in internal energy during the process will be zero.