Question

A monatomic ideal gas is given 200 J of energy at constant pressure. The increase in internal energy
of gas will be

(1) 80 J
(2) 100 J
(3) 120 J
(4) 200 J

Answer=(3)​

Answer 1

Answer:3

Explanation:

There may be another method to solve this problem so don't get confused

First I am assuming the energy is supplied in the form of heat

Next at const pressure q=∆H

Now, ∆H=∆E+nR∆T

Again, ∆E=f/2 nR∆T

=3/2 nR∆T (For monoatomic

gas for=1)

Therefore, ∆H=1.5nR∆T+nR∆T

200=2.5nR∆T

nR∆T=80

So ∆E=1.5•80

=120J

Plz mark this as brainliest.... I have never got a brainliest

Answer 2

Explanation:

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