Question

A money box contains $1 coins, $2 coins, $5 coins and $10 coins. The number of 10 coins is four times the number of 5 coins, eight times the number of 2 coins and sixteen times the number of * 1 coins. If all the money in the money box adds upto *555, find the number of 10 coins in it. (Hint: Let the number of $10 coins be x. Then, 10x + 5(x/4)+2(x/8)+1(x/16)=555] ​

Answer 1

Let the number of one rupee coins be 5x and that of two rupee coins be 6x.
Now, value of 5x one rupee coins = Rs. 1×5x= Rs. 5x and
value of 6x two rupee coins = Rs. 2×6x= Rs. 12x
Given, value of coins = Rs. 85
⇒5x+12x=85
⇒17x=85
⇒x=5
So, the number of two rupee coins =6×5=30
Hence, there are total 30 two rupee coins in the money box.