Question

A monkey ascends a pole and go 4meters in first time and slips down 2 ln how much time monkey teach at the top of pole of 10 m height

Answer 1

Answer:Height of the pole (x) = 15 m.

Climbed distance per minute(y)= 4m

Slips (y) = 2 m in next minute.

So, in 2 minute he climbs 2 m.

We take, 2 minute = 1 unit of time.

t = 2 minutes.

You can calculate required time by this formula: ( We are calculating it for 14 m.)

Reqd. time =[(ht. of pole - slipped distance)/(climbed distance - slipped distance)]*t

= [(x-z)/(y-z)]*t;

= [(14 - 2) / (4 -2)] *2

= (12/2) *2

= 6 *2

= 12 minutes.

And the last 1 m monkey will climb in 45 second becouse one he get up did not get slipped down.

So, Total time = 12 minutes 45 seconds.

Step-by-step explanation: