A monkey climb 30 feet at the beginning of each
hour and rests for a while when he slips back 20
feet before he again starts climbing in the
beginning of the next hour. If he begins his
ascent at 8.00 am, at what time will he first touch
a flag at 120 feet from the ground?
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Answer:
Net distance in Ist 9 hrs=10x9=90 ft.
Then in the next attempt , it will touch the flag, ie, 10 th hour
8am +10hr = 6.pm
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