A monkey climbs a 15ft pole to reach the banana tied at the top of the pole, if the monkey climbs at a rate of 3ft/s and slips 2ft over the next secound, find how much time will it takes for the monkey to reach the banana?
mathskhongstid:
Please give the details explanation of how the speed is 1/4ft per sec
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Length of pole = 15ft
monkey climbs 3ft in 1 second and slips 2ft in next second.
So it climbs = 3ft - 2ft = 1ft in 2 second
When it climbs the last 3ft, it will reach the top and won't slip back.
So it will climb the last 3 ft in 1 second.
The rest height = 15 - 3 = 12ft
since it climbs 1ft in 2 seconds, it will climb 12ft in = 12×2 = 24 seconds
So total time = 24 + 1 = 25 seconds.
Thus the monkey will climb the pole in 25 seconds.
monkey climbs 3ft in 1 second and slips 2ft in next second.
So it climbs = 3ft - 2ft = 1ft in 2 second
When it climbs the last 3ft, it will reach the top and won't slip back.
So it will climb the last 3 ft in 1 second.
The rest height = 15 - 3 = 12ft
since it climbs 1ft in 2 seconds, it will climb 12ft in = 12×2 = 24 seconds
So total time = 24 + 1 = 25 seconds.
Thus the monkey will climb the pole in 25 seconds.
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