Question

a monkey is climbing a vertical pillar with a velocity of 5ms^-1 and a boy is running towards pillar witha velocity of 5√3ms^-1. velocity of boy relative to monkey is​

Answer 1

Given:

$V_{m}=5\frac{m}{sec} j$

$V_{b}=5\sqrt{3} \frac{m}{sec} i$

To Find:

Velocity of boy relative to monkey.

Explanation:

$V_{bm}=V_{b}-V_{m}$

$=(5\sqrt{3}i-5j) \frac{m}{sec}$

The magnitude of $V_{bm}$ is given by:

$\sqrt{5^{2}+(5\sqrt{3})^{2} }$

$=\sqrt{100}$

$=10$

$|V_{bm}|=10\frac{m}{sec}$