A monkey is sitting on a tree limb. The limb exerts a normal force of 20 N and frictional force of 15 N. The magnitude of total force exerted by the limb on the monkey is
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The limb exerts a normal force 48 N and frictional force of 20 N. Resultant magnitude of the force,
R= (48) 2 +(20) 2
= 2304+400
= 2704
=52 N
Explanation:
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