Question

A monkey is sitting on a tree limb. The limb exerts a normal force of 48 N and a frictional force of 20 N. Find the magnitude of the total force exerted by the limb on the monkey.
Concept of Physics - 1 , HC VERMA , Chapter "The Force".

Answer 1

Hi...


Total force = root (normal force) ^2+ (frictional force)^2
Thus total force = root (48)^2 + (20)^2
Total force = root 2704
= 52N..

Hope this helps u!!

Answer 2

Hello Dear.

Here in the question it is given that :-

the limb exert a normal force i.e 48 N.

also The limb exert a frictional force i.e 20 N .

So the magnitude of the resultant force 

R = $\sqrt{N^{2} + F ^{2} _{f} }$ 
R = $\sqrt{48^2 + 20^2}$
R = √2704
R = 52 N

Hence the magnitude of the total force exerted through the limb on monkey is 52 N.


Hope it Helps. :-)