Question

A monkey of mass 15 kg is climbing a rope fixed to a ceiling. If it wishes to go up with an acceleration of 1 m/s2, how much force should it apply on the rope? If the rope is 5 m long and the monkey starts from rest, how much time will it take to reach the ceiling?

Answer 1

given:

mass=15kg

Acceleration of the monkey in the upward direction, a = 1 m/s2

The free-body diagram of the monkey is given in the attachment:

From the free-body diagram:

T − [15g + 15(a)] = 0

T − [15g + 15(1)] = 0

⇒ T = 5 (10 + 1)

⇒ T = 15 × 11 = 165 N

The monkey should apply a force of 165 N to the rope.

Initial velocity, u = 0

s = 5 m

Using,

s=ut+1/2at², we get:

5=0+1/2×1×t²

⇒t²=5×2⇒t=√10 s

Hence, the time required to reach the ceiling is 10 s.

Answer 2

Answer:

Explanation:see the attachment