A monkey of mass 15 kg is holding a vertical rope. The rope will not break when a mass of 30 kg is suspended from it but will break if the mass exceeds 30 kg what is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s²) (1) 15 m/s² (2) 10 m/s² (3) 25 m/s² (4) 20 m/s²
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Answer:
2.5 m/s^2
Explanation:
Let the acceleration of the monkey be a.
Mass of monkey m=20 kg
Breaking force required T=25×10=250 N
Equation of motion : ma=T−mg
Thus we get, T=m(a+g)
Or 250=(20)(a+10)
⟹ a=2.5 m/s^2
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