Question

A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25kg. What is the maximum acceleration with which monkey can climb up along the rope?

Answer 1

Is this from hc verma

Answer 2

The rope will not break unto 20kg it means it is its tension.

Thus balance condition

is  T-mg=ma

25g-20g= 20a    (g=10)     thus on solving a=50/20= 2.5m/s^ (ans)

So this  monkey can have max acceleration of2.5 if he really wants to climb the tree

Let the Monkey be climbing up with an acceleration 'a'.

Tension in string =m(g+a)

=Breaking force

20(g+a)=25×g

a=g4

=104

=2.5m/s2