Question

A monkey of mass 20 kg is holding a vertical rope . The rope will not break when a mass of 25kg is suspended from it but will break if the mass exceeds 25kg . What is the max acc with which the monkey can climb up the rope

Answer 1

The rope will not break unto 20kg it means it is its tension.

Thus balance condition

is  T-mg=ma

25g-20g= 20a    (g=10)     thus on solving a=50/20= 2.5m/s^ (ans)

So this  monkey can have max acceleration of2.5 if he really wants to climb the tree

Let the Monkey be climbing up with an acceleration 'a'.

Tension in string =m(g+a)

=Breaking force

20(g+a)=25×g

a=g4

=104

=2.5m/s2