Question

A monkey of mass 30 kg climbs a rope which can withstand a maximum temsion 360N. Find the
maximum acceleration which this rope can tolerate for the climbing of monkey)
(g = 10 m/s)​

Answer 1

Answer:

We know,

T - mg = ma

here,

T = 360 n

m = 30kg

g = 9.2 m/s²

a = ?

hence,

360 - 30*9.2 = 30a

or, 30a = 360 - 276 = 84

or, a = 84/30 = 2.8

therefore accelaration = 2.8 m/s²

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Using Newton’s 2nd law:

ΣFy=may

T−mg=may

or

ay=Tm−g=420N30kg−9.81ms2=4.19ms2

Note that if the monkey is not moving, then ay=0 and the rope tension is simply equal to his weight.