A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600
N. What is the tension in the rope if the monkey climbs up with an acceleration of 6 m s^-2
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Answered by
11
Explanation:
Mass of the monkey, m = 40 kg
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 6 m/s
2
upward
Using Newtons second law of motion, we can write the equation of motion as:
T mg = ma
T = m(g + a)
= 40 (10 + 6)
= 640 N
Since T > T
max
, the rope will break in this case.
Answered by
2
T-mg=ma
T= m(g+a)
T=40×16
T=640N
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