Question

a monkey of mass m =30 kg is climbing up a rope with an acceleration a=5ms^-2 is related to the rope. The rope passes over a frictionless fixed Pulley and has a block of mass M =15 kg at the other end as shown in figure find (1)acceleration of the rope (2)acceleration of monkey (3)tension in the rope. Take g=10ms^-2​

Answer 1

Answer:

monkey's force

=30*5=150kg.m/sec/sec

Explanation:

Force exerted by block

=15*10kg.m/sec^2

=150kg.m/sec^2

(3)tension in rope

=addition of these 2 forces

=300 kg.m /sec^2...ANSWER 3

(2)acceleration of monkey

=5m/sec/sec...ANSWER 2

Answer 2

Concept Introduction:-

Mass is a numerical inertia is a fundamental feature of all stuff that can be measured in physics.

Given Information:-

We have been given that a monkey of mass m$=30$ kg is climbing up a rope with an acceleration a $=5ms^{-2}$ is related to the rope. The rope passes over a frictionless fixed Pulley and has a block of mass M$=15$ kg

To Find:-

We have to find that $(1)$acceleration of the rope $(2)$acceleration of monkey $(3)$tension in the rope

Solution:-

According to the problem

$(1)$Force exerted by block

$=15*10kg.m/sec^2=150kg.m/sec^2$

$(2)$acceleration of monkey

$=5m/sec^{-2}$

$(3)$tension in rope

$=$addition of these $2$ forces

$=300 kg.m /sec^2$

Final Answer:-

$(1)$ acceleration of the rope is $150kg.m/sec^2$$(2)$ acceleration of monkey is $5m/sec^{-2}$ $(3)$ tension in the rope is $300 kg.m /sec^2$.

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