Question

A monkey of mass m kg slides down a light rope attached to a fixed spring balance. with an
acceleration a. The reading of this balance is w kg (g = acceleration due to gravity) (AIIMS 2009)
(1) m-wg
g-a
(2) m=w1-a
n
(3) the force of friction exerted by the rope on the monkey is m(g-a) Newton
(4) the tension in the rope is wg Newton​

Answer 1

(3) the force of friction exerted by the rope on the monkey is m(g-a) Newton

Explanation:

mass of monkey = m kg

Since the monkey is moving down with an acceleration a when the spring balance reads w kg.

∴Net force of friction on the rope:

$f=m.g-m.a$

$f=m(g-a)$

This difference in due to the acceleration on monkey down the rope.

TOPIC: tension in rope, friction, mass and weight

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