A monkey on a coconut tree throws a coconut horizontally from a height of 13 m. The coconut lands 5.0 m from the tree. With what velocity was the coconut thrown?
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Answer:
3.1 m/s
Explanation:
x = vt cos∝ , y = vtsin∝ - gt²/2 , the coconut thrown horizontally ∝ = 0
x = vt , y = - gt²/2 = -13 , t = √26/g
v = x/t = 5 √(g/26) = 5 √10/26 = 3.1 m/s
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