A monkey sitting on a branch of tree 20m high drops a mango directly above the head of boy as he runs with speed 1.5ms^-1 under tree . How far behind boy does the mango hit ground
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Answered by
1
Answer:
(2s/g)^1/2
=(2*20/10)^1/2
=4sec
distance travelled by man
=1.5*4
=6m
therefore its 6m behind us
Answered by
2
The correct answer for your ques is *3m*
Time taken by the mango to hit the ground
t = (2h/g)^1/2
= √(2*20)/10
= 2sec
Distance travelled by the boy = v*t
=1.5*2=3m
Hope it helps u
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