A monkey starts climbing up a 20 ft. tall pole. each hour it hops 3 ft. and slips back 2 ft. how much time would it take the monkey to reach the top?
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each hour it hops 3 ft and slips back 2 ft. therefore the progress each hour is 1 ft. (3-2)..
hence the monkey would reach the top in 20 hours..
hope it helps!
NupurJha:
but its not in options
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Answer:
18 hours...
Step-by-step explanation:
As in an hour the monkey climbs 3ft and slips 2ft, distance the monkey climbs in an hour will be = 3ft-2ft = 1ft.
So the time it takes to climb the first 17 feet will be = 17 hrs
After climbing 17 ft, in the last 3ft the monkey climbs, it reaches the top and doesn’t slip back. So, it takes an hour to climb these last 3 feet.
Hence, the total time it takes to cimb will be = 17hrs+1hr = 18hrs.
PLS ADD IT AS A BRAINLIEST........
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