Question

A monkey starts climbing up a 20 ft. tall pole. each hour it hops 3 ft. and slips back 2 ft. how much time would it take the monkey to reach the top?

Answer 1

each hour it hops 3 ft and slips back 2 ft. therefore the progress each hour is 1 ft. (3-2)..

hence the monkey would reach the top in 20 hours..

hope it helps!

Answer 2

Answer:

18 hours...

Step-by-step explanation:

As in an hour the monkey climbs 3ft and slips 2ft, distance the monkey climbs in an hour will be = 3ft-2ft = 1ft.

So the time it takes to climb the first 17 feet will be = 17 hrs

After climbing 17 ft, in the last 3ft the monkey climbs, it reaches the top and doesn’t slip back. So, it takes an hour to climb these last 3 feet.

Hence, the total time it takes to cimb will be = 17hrs+1hr = 18hrs.

PLS ADD IT AS A BRAINLIEST........