Question

A monkey tries to climbing a wet tree of height 56 metre and is able to ascend at 12 metre/minute while it slips at 4 metre/minute in alternate minutes.How much time will be required for it to reach the top

Answer 1

Ans: 12 m & 40 sec  2m 8,4m 18,8m 32,12m 48 & 12m&40s 56

Answer 2

[ (total height-climb height)/(climb height-slip height) ]*(time to climb and slip minutes)+1

{Formula works for all similar questions}

here

total height=/56

1 climb height=12

1 slip height=4

time to climb and slip minutes=time taken for 1 consecutive climb and slip=2 min

i.e; 1 minute to climb and another 1 minute to slip=2min

Note1:If slip is also in same minute then=1 min

“+1″ as last step.

So,

[(56–12)/(12–4)]*2+1

[44/8]*2+1

[5.5]*2+1

11+1

12 min.

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I Hope it would help yelped you

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