Physics, asked by ShreejaT, 4 months ago

A mono atomic ideal gas, initially at tempearture Ti is enclosed in a cylinder fitted with a frictionless piston. The gas is
allowed to expand adiabatically to a temperature T2 by releasing the position suddenly. If Li and L2 are the lengths of
the gas column before and after expansion respectively, then T1/T2 is given by
(A)(l1/l2) ^2/3
(b) l1/l2
(C)l2/l1
(D) (l2/l1) ^2/3​

Answers

Answered by vimalavishnu477
1

Answer:

option d is the correct answer

Explanation:

For adiabetic process, TVγ–1 = constant For mono atomic gas, γ = (CP / CV) = [(5/2) / (3/2)] = (5/3)  ∴  TV[(5/3) – 1] = constant ∴  TV(2/3) = constant ∴  (T1 / T2) = (V2 / V1)2/3  L1 & L2 are length of gas column at T1 & T2 respectively. ∴   Hence (V2 / V1) = (L2 / L1) as volume α length (T1 / T2) = (L2 / L1)2/3     

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