Question

A mono-atomic ideal gas undergoes a process in which the ratio of P to V at any instant is constant and equals to 1. What is the molar heat capacity of the gas(a) $\frac{3R}{2}$(b) 2 R (c) 0 (d) $\frac{5R}{2}$

Answer 1

p1v1=rt

CV=3/2R

p/v =1

p=v

dq = CvdT +pdV

for 1 noble gas

PV=rt

on differentiating,

pdV+VdP= Rdt

2pdv=Rdt

pdV= RdT/2

rest in the figure