A monoacid organic base (0.0915 g)requires 15 cm3 of N/20 HCl forcomplete neutralization. The molarmass of the base is
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Answer:
milliequivalence of base= milliequivalence of acid
weight of organic base/equivalent mass = normality* volume
here equivalent mass= molar mass ( as it is monoacid base)
let M be the molar mass
so substitute values,
0.0915/M = 1/20* 15/1000
M= 122 g/mol
Explanation:hope it helps
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