A monoatomic gas at pressure P1 and V1 is compressed adiabatically to 1/8th its original volume. What is the final pressure of the gas? (1) 64P1 (2) P1 (3) 16P1 (4) 32 P1
Answers
Answered by
5
hey
here's ur answer!
let P1 be x
and let V1 be y
new volume (V2) = 1/8 * V1
= 1/8 * y
= y/8
P2 = ?
##NOW,
ACCORDING TO BOYLE'S LAW,
P1/V1 = P2/V2
=> x/y = P2/ (y/8)
=> x/y = 8 P2/y
=> x = 8P2
=> P1 = 8P2
=> P1/8 = P2 [answer]
hope it helps!
here's ur answer!
let P1 be x
and let V1 be y
new volume (V2) = 1/8 * V1
= 1/8 * y
= y/8
P2 = ?
##NOW,
ACCORDING TO BOYLE'S LAW,
P1/V1 = P2/V2
=> x/y = P2/ (y/8)
=> x/y = 8 P2/y
=> x = 8P2
=> P1 = 8P2
=> P1/8 = P2 [answer]
hope it helps!
Answered by
0
Answer:
32P1
Explanation:
In this,the system is adiabatic.
So, PV^Y is used.
For monoatomic,Y =5/3
Attachments:
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