Question

A monoatomic gas at pressure P1 and V1 is compressed adiabatically to 1/8th its original volume. What is the final pressure of the gas? (1) 64P1 (2) P1 (3) 16P1 (4) 32 P1

Answer 1

The correct answer is option (4) - 32 P1

Solution:

Let’s assume the initial pressure to be P, final pressure to be P2 and initial volume to be V.

 

It is given that for a monoatomic gas γ = 5/3

 

For adiabatic process PV^γ = constant 

 

PV^5/3 = P (V/8)^5/3

P2 = P(8)^5/3

P2 = P × 2⁵

Therefore, P2 = 32P

Answer 2

The answer is provided in the attachment.