A monoatomic gas at pressure P1 and volume V1 is compressed adiabatically to 1/8th its original volume. What is the final pressure of the gas?
Answers
Answered by
6
Answer:
P2 = 32P
Explanation:
Let’s assume the initial pressure to be P, final pressure to be P2 and initial volume to be V.
It is given that for a monoatomic gas γ = 5/3
For adiabatic process PV^γ = constant
PV^5/3 = P (V/8)^5/3
P2 = P(8)^5/3
P2 = P × 2⁵
Therefore, P2 = 32P
Answered by
0
Answer:
As the compression is adiabatic, therefore, change in q(heat) = 0
Final Pressure = 32 * Initial Pressure.
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