Question

A monoatomic ideal gas is given 200J of energy at constant pressure. the increase in the internal energy of the gas will be​

Answer 1

Answer:

SEE THE ATTACHMENT.......... ♥

Answer 2

The internal energy is 142.8 J.

Explanation:

Given that,

Energy = 200 J

We know that,

At constant pressure, work done is zero.

At constant volume, internal energy

$\Delta U=nC_{v}\Delta T$

At constant pressure, Heat

$Q=nc_{p}\Delta T$

We know that,

$\dfrac{c_{v}}{c_{p}}=\gamma$

For monoatomic gas,

$\gamma=\dfrac{3}{2}$

We need to calculate the increases in the internal energy

Using first law of thermodynamic

$\Delta Q=\Delta U+W$

$\dfrac{\Delta Q}{\Delta U}= \dfrac{nC_{p}\Delta T}{nC_{v}\Delta T}$

Put the value into the formula

$\dfrac{200}{\Delta U}=1.4$

$\Delta U=142.8\ J$

Hence, The internal energy is 142.8 J.

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Topic : internal energy

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