a monobasic weak acid solution which is 0.002 M has ph value equal to 5 the percentage ionisation value of the acid in the solution will be
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A monobasic acid solution has pH value of 5. Its molarity is 0.005 M. The degree of ionisation of the acid is
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The percentage ionisation value of the acid in the solution will be 0.5%
Let the degree of ionisation be α.
If the concentration of the solution is considered to be 'c' then,
α = [H⁺]/c
where, [H⁺] is the concentration of H⁺ ions in the solution.
Given, pH =5.
We know that, pH is the negative logartithm of the conc. of H⁺ ions.
So, [H⁺] = 10⁻⁵ M,
c = 0.002M
Replacing the values, we get,
α = (10⁻⁵ )/0.002
= 0.005
Expressing it as a percentage, we get
(0.005*100)%
= 0.5%
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