A monochromatic radiation was beamed on a distant planet from E16h and the reflectionwas received after seven minutes. If the velocity of the signal is 3×108 m/s, then the distance between the E16h and Planet in meters is
(1) 3.15 × 108
(2) 3 × 1010
(3) 6.3 × 1010
(4) 3.15 × 1010
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total distance travelled=3×10^8×7×60
=1.26×10^11
but this is total distance travelled by the signal
therefore the distance between planet and E16h will be
(1.26×10^11)/2
=6.3×10^10
=1.26×10^11
but this is total distance travelled by the signal
therefore the distance between planet and E16h will be
(1.26×10^11)/2
=6.3×10^10
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